Base | Representation |
---|---|
bin | 111101100001010001… |
… | …1000111011000000000 |
3 | 110122000011220222020102 |
4 | 1323002203013120000 |
5 | 4131031412112112 |
6 | 140405240101532 |
7 | 12354612001652 |
oct | 1730243073000 |
9 | 418004828212 |
10 | 132113004032 |
11 | 5103538a359 |
12 | 217304648a8 |
13 | c5c5896689 |
14 | 6573d7c6d2 |
15 | 36835e8bc2 |
hex | 1ec28c7600 |
132113004032 has 20 divisors (see below), whose sum is σ = 263967975876. Its totient is φ = 66056501760.
The previous prime is 132113003993. The next prime is 132113004061. The reversal of 132113004032 is 230400311231.
It is a junction number, because it is equal to n+sod(n) for n = 132113003995 and 132113004013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129016094 + ... + 129017117.
Almost surely, 2132113004032 is an apocalyptic number.
It is an amenable number.
132113004032 is a deficient number, since it is larger than the sum of its proper divisors (131854971844).
132113004032 is an frugal number, since it uses more digits than its factorization.
132113004032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258033229 (or 258033213 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 132113004032 its reverse (230400311231), we get a palindrome (362513315263).
The spelling of 132113004032 in words is "one hundred thirty-two billion, one hundred thirteen million, four thousand, thirty-two".
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