Base | Representation |
---|---|
bin | 111101100001010001… |
… | …1010011001100010101 |
3 | 110122000012000102122012 |
4 | 1323002203103030111 |
5 | 4131031420134222 |
6 | 140405241114005 |
7 | 12354612263042 |
oct | 1730243231425 |
9 | 418005012565 |
10 | 132113052437 |
11 | 51035412763 |
12 | 21730488905 |
13 | c5c58b2712 |
14 | 6573d921c9 |
15 | 36836081e2 |
hex | 1ec28d3315 |
132113052437 has 2 divisors, whose sum is σ = 132113052438. Its totient is φ = 132113052436.
The previous prime is 132113052433. The next prime is 132113052451. The reversal of 132113052437 is 734250311231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 77614616836 + 54498435601 = 278594^2 + 233449^2 .
It is an emirp because it is prime and its reverse (734250311231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132113052437 - 22 = 132113052433 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132113052433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056526218 + 66056526219.
It is an arithmetic number, because the mean of its divisors is an integer number (66056526219).
Almost surely, 2132113052437 is an apocalyptic number.
It is an amenable number.
132113052437 is a deficient number, since it is larger than the sum of its proper divisors (1).
132113052437 is an equidigital number, since it uses as much as digits as its factorization.
132113052437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 132113052437 its reverse (734250311231), we get a palindrome (866363363668).
The spelling of 132113052437 in words is "one hundred thirty-two billion, one hundred thirteen million, fifty-two thousand, four hundred thirty-seven".
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