Base | Representation |
---|---|
bin | 11110000010100000110000… |
… | …101001110110000000000111 |
3 | 122022202222100112100111002021 |
4 | 132002200300221312000013 |
5 | 114304023443114103143 |
6 | 1144552201035224011 |
7 | 36553631222604124 |
oct | 3602406051660007 |
9 | 568688315314067 |
10 | 132114010300423 |
11 | 39106267678198 |
12 | 129986b68a8007 |
13 | 58943b4103388 |
14 | 248a4d06a774b |
15 | 10418c677aced |
hex | 782830a76007 |
132114010300423 has 2 divisors, whose sum is σ = 132114010300424. Its totient is φ = 132114010300422.
The previous prime is 132114010300399. The next prime is 132114010300427. The reversal of 132114010300423 is 324003010411231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132114010300423 is a prime.
It is a super-2 number, since 2×1321140103004232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132114010300427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057005150211 + 66057005150212.
It is an arithmetic number, because the mean of its divisors is an integer number (66057005150212).
Almost surely, 2132114010300423 is an apocalyptic number.
132114010300423 is a deficient number, since it is larger than the sum of its proper divisors (1).
132114010300423 is an equidigital number, since it uses as much as digits as its factorization.
132114010300423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 132114010300423 its reverse (324003010411231), we get a palindrome (456117020711654).
The spelling of 132114010300423 in words is "one hundred thirty-two trillion, one hundred fourteen billion, ten million, three hundred thousand, four hundred twenty-three".
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