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13212012230 = 251777717719
BaseRepresentation
bin11000100110111111…
…10100111011000110
31021002202201202120022
430103133310323012
5204024233342410
610023003135142
7645256152044
oct142337647306
937082652508
1013212012230
11566a92237a
1226888144b2
1313272a3721
148d4997394
15524d80455
hex3137f4ec6

13212012230 has 16 divisors (see below), whose sum is σ = 25180541280. Its totient is φ = 4973933952.

The previous prime is 13212012223. The next prime is 13212012239. The reversal of 13212012230 is 3221021231.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a junction number, because it is equal to n+sod(n) for n = 13212012199 and 13212012208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13212012239) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38858690 + ... + 38859029.

It is an arithmetic number, because the mean of its divisors is an integer number (1573783830).

Almost surely, 213212012230 is an apocalyptic number.

13212012230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13212012230 is a deficient number, since it is larger than the sum of its proper divisors (11968529050).

13212012230 is a wasteful number, since it uses less digits than its factorization.

13212012230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77717743.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13212012230 its reverse (3221021231), we get a palindrome (16433033461).

Subtracting from 13212012230 its reverse (3221021231), we obtain a palindrome (9990990999).

The spelling of 13212012230 in words is "thirteen billion, two hundred twelve million, twelve thousand, two hundred thirty".

Divisors: 1 2 5 10 17 34 85 170 77717719 155435438 388588595 777177190 1321201223 2642402446 6606006115 13212012230