Base | Representation |
---|---|
bin | 1100000001000010100111… |
… | …1001010110010111000111 |
3 | 1201210001112112212102220221 |
4 | 3000100221321112113013 |
5 | 3212431210202132101 |
6 | 44033304054205211 |
7 | 2532352141420111 |
oct | 300205171262707 |
9 | 51701475772827 |
10 | 13212022302151 |
11 | 42342071754a2 |
12 | 15946b3653807 |
13 | 74ab7194a33a |
14 | 339672a8c3b1 |
15 | 17da1d2d4aa1 |
hex | c0429e565c7 |
13212022302151 has 2 divisors, whose sum is σ = 13212022302152. Its totient is φ = 13212022302150.
The previous prime is 13212022302119. The next prime is 13212022302181. The reversal of 13212022302151 is 15120322021231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13212022302151 - 25 = 13212022302119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13212022302181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606011151075 + 6606011151076.
It is an arithmetic number, because the mean of its divisors is an integer number (6606011151076).
Almost surely, 213212022302151 is an apocalyptic number.
13212022302151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13212022302151 is an equidigital number, since it uses as much as digits as its factorization.
13212022302151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13212022302151 its reverse (15120322021231), we get a palindrome (28332344323382).
The spelling of 13212022302151 in words is "thirteen trillion, two hundred twelve billion, twenty-two million, three hundred two thousand, one hundred fifty-one".
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