Base | Representation |
---|---|
bin | 11110000010100111010010… |
… | …100011000100100011100111 |
3 | 122022210122110010222022102211 |
4 | 132002213102203010203213 |
5 | 114304132322434320234 |
6 | 1144555320451344251 |
7 | 36554300035146406 |
oct | 3602472243044347 |
9 | 568718403868384 |
10 | 132121021401319 |
11 | 39109235214055 |
12 | 12999b328b2087 |
13 | 5894c607c4ca2 |
14 | 248a9978b363d |
15 | 1041b87039164 |
hex | 7829d28c48e7 |
132121021401319 has 2 divisors, whose sum is σ = 132121021401320. Its totient is φ = 132121021401318.
The previous prime is 132121021401289. The next prime is 132121021401371. The reversal of 132121021401319 is 913104120121231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132121021401319 - 211 = 132121021399271 is a prime.
It is a super-2 number, since 2×1321210214013192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132121021401419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060510700659 + 66060510700660.
It is an arithmetic number, because the mean of its divisors is an integer number (66060510700660).
Almost surely, 2132121021401319 is an apocalyptic number.
132121021401319 is a deficient number, since it is larger than the sum of its proper divisors (1).
132121021401319 is an equidigital number, since it uses as much as digits as its factorization.
132121021401319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 132121021401319 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, twenty-one million, four hundred one thousand, three hundred nineteen".
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