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132121240403143 is a prime number
BaseRepresentation
bin11110000010100111011111…
…100110011111110011000111
3122022210200000102001202110111
4132002213133212133303013
5114304133300020400033
61144555354313333451
736554305334504605
oct3602473746376307
9568720012052414
10132121240403143
11391093378a53a2
1212999b94107287
135894c96ca3274
14248a9b8a00875
151041b9b3987cd
hex7829df99fcc7

132121240403143 has 2 divisors, whose sum is σ = 132121240403144. Its totient is φ = 132121240403142.

The previous prime is 132121240403099. The next prime is 132121240403147. The reversal of 132121240403143 is 341304042121231.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132121240403143 - 237 = 131983801449671 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132121240403147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060620201571 + 66060620201572.

It is an arithmetic number, because the mean of its divisors is an integer number (66060620201572).

Almost surely, 2132121240403143 is an apocalyptic number.

132121240403143 is a deficient number, since it is larger than the sum of its proper divisors (1).

132121240403143 is an equidigital number, since it uses as much as digits as its factorization.

132121240403143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 132121240403143 its reverse (341304042121231), we get a palindrome (473425282524374).

The spelling of 132121240403143 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, two hundred forty million, four hundred three thousand, one hundred forty-three".