Base | Representation |
---|---|
bin | 11110000010100111100100… |
… | …000000011010000100101100 |
3 | 122022210200012120010022210101 |
4 | 132002213210000122010230 |
5 | 114304133422430214200 |
6 | 1144555405513320444 |
7 | 36554310222610066 |
oct | 3602474400320454 |
9 | 568720176108711 |
10 | 132121314304300 |
11 | 39109375590432 |
12 | 12999bb4a06124 |
13 | 5894ca93a9669 |
14 | 248a9c475a736 |
15 | 1041ba2ae526a |
hex | 7829e401a12c |
132121314304300 has 72 divisors (see below), whose sum is σ = 305322879085056. Its totient is φ = 49452275573760.
The previous prime is 132121314304261. The next prime is 132121314304307. The reversal of 132121314304300 is 3403413121231.
It is not an unprimeable number, because it can be changed into a prime (132121314304307) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 224325612 + ... + 224913811.
It is an arithmetic number, because the mean of its divisors is an integer number (4240595542848).
Almost surely, 2132121314304300 is an apocalyptic number.
132121314304300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132121314304300 is an abundant number, since it is smaller than the sum of its proper divisors (173201564780756).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132121314304300 is a wasteful number, since it uses less digits than its factorization.
132121314304300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 449239627 (or 449239620 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 132121314304300 its reverse (3403413121231), we get a palindrome (135524727425531).
The spelling of 132121314304300 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, three hundred fourteen million, three hundred four thousand, three hundred".
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