Base | Representation |
---|---|
bin | 1100000001000011000010… |
… | …0111110011100001111000 |
3 | 1201210001211102012101012210 |
4 | 3000100300213303201320 |
5 | 3212431423044043134 |
6 | 44033323204535120 |
7 | 2532355011514551 |
oct | 300206047634170 |
9 | 51701742171183 |
10 | 13212135143544 |
11 | 4234264937947 |
12 | 15947253b14a0 |
13 | 74ab8c138aac |
14 | 339683a63328 |
15 | 17da281742e9 |
hex | c04309f3878 |
13212135143544 has 32 divisors (see below), whose sum is σ = 33030428901840. Its totient is φ = 4404032908800.
The previous prime is 13212135143527. The next prime is 13212135143563. The reversal of 13212135143544 is 44534153121231.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13947214 + ... + 14864354.
Almost surely, 213212135143544 is an apocalyptic number.
It is an amenable number.
13212135143544 is an abundant number, since it is smaller than the sum of its proper divisors (19818293758296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13212135143544 is a wasteful number, since it uses less digits than its factorization.
13212135143544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1517391 (or 1517387 counting only the distinct ones).
The product of its digits is 172800, while the sum is 39.
Adding to 13212135143544 its reverse (44534153121231), we get a palindrome (57746288264775).
The spelling of 13212135143544 in words is "thirteen trillion, two hundred twelve billion, one hundred thirty-five million, one hundred forty-three thousand, five hundred forty-four".
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