Search a number
-
+
132122726543 is a prime number
BaseRepresentation
bin111101100001100100…
…0001101000010001111
3110122000212012221000102
41323003020031002033
54131041404222133
6140410224321315
712355060434323
oct1730310150217
9418025187012
10132122726543
115103a91aa95
122173377323b
13c5c78bbb42
14657538d983
1536843b97e8
hex1ec320d08f

132122726543 has 2 divisors, whose sum is σ = 132122726544. Its totient is φ = 132122726542.

The previous prime is 132122726473. The next prime is 132122726551. The reversal of 132122726543 is 345627221231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132122726543 - 210 = 132122725519 is a prime.

It is a super-3 number, since 3×1321227265433 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132122726497 and 132122726506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132122725543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061363271 + 66061363272.

It is an arithmetic number, because the mean of its divisors is an integer number (66061363272).

Almost surely, 2132122726543 is an apocalyptic number.

132122726543 is a deficient number, since it is larger than the sum of its proper divisors (1).

132122726543 is an equidigital number, since it uses as much as digits as its factorization.

132122726543 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120960, while the sum is 38.

Adding to 132122726543 its reverse (345627221231), we get a palindrome (477749947774).

The spelling of 132122726543 in words is "one hundred thirty-two billion, one hundred twenty-two million, seven hundred twenty-six thousand, five hundred forty-three".