13212402415111 has 2 divisors, whose sum is σ = 13212402415112. Its totient is φ = 13212402415110.

The previous prime is 13212402415099. The next prime is 13212402415123. The reversal of 13212402415111 is 11151420421231.

It is a balanced prime because it is at equal distance from previous prime (13212402415099) and next prime (13212402415123).

It is an emirp because it is prime and its reverse (11151420421231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13212402415111 - 2⁹ = 13212402414599 is a prime.

It is a super-2 number, since 2×13212402415111² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13212402415111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13212402416111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606201207555 + 6606201207556.

It is an arithmetic number, because the mean of its divisors is an integer number (6606201207556).

Almost surely, 2^{13212402415111} is an apocalyptic number.

13212402415111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212402415111 is an equidigital number, since it uses as much as digits as its factorization.

13212402415111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 28.

Adding to 13212402415111 its reverse (11151420421231), we get a palindrome (24363822836342).

The spelling of 13212402415111 in words is "thirteen trillion, two hundred twelve billion, four hundred two million, four hundred fifteen thousand, one hundred eleven".