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13212412143341 is a prime number
BaseRepresentation
bin1100000001000100000100…
…1000011110011011101101
31201210002112201102102111112
43000101001020132123231
53212433010002041331
644033410502001405
72532364614131255
oct300210110363355
951702481372445
1013212412143341
1142343972319a4
1215947a2116265
1374ac046429b8
143396ac76a965
1517da4263d32b
hexc044121e6ed

13212412143341 has 2 divisors, whose sum is σ = 13212412143342. Its totient is φ = 13212412143340.

The previous prime is 13212412143319. The next prime is 13212412143349. The reversal of 13212412143341 is 14334121421231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11656392909316 + 1556019234025 = 3414146^2 + 1247405^2 .

It is a cyclic number.

It is not a de Polignac number, because 13212412143341 - 26 = 13212412143277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13212412143298 and 13212412143307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13212412143349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606206071670 + 6606206071671.

It is an arithmetic number, because the mean of its divisors is an integer number (6606206071671).

Almost surely, 213212412143341 is an apocalyptic number.

It is an amenable number.

13212412143341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212412143341 is an equidigital number, since it uses as much as digits as its factorization.

13212412143341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824, while the sum is 32.

Adding to 13212412143341 its reverse (14334121421231), we get a palindrome (27546533564572).

The spelling of 13212412143341 in words is "thirteen trillion, two hundred twelve billion, four hundred twelve million, one hundred forty-three thousand, three hundred forty-one".