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13212413105237 is a prime number
BaseRepresentation
bin1100000001000100000100…
…1100001001010001010101
31201210002112210020021222022
43000101001030021101111
53212433010223331422
644033410534342525
72532364625245523
oct300210114112125
951702483207868
1013212413105237
114234397829655
1215947a24baa45
1374ac048bb778
143396ac93b313
1517da4277d342
hexc0441309455

13212413105237 has 2 divisors, whose sum is σ = 13212413105238. Its totient is φ = 13212413105236.

The previous prime is 13212413105231. The next prime is 13212413105323. The reversal of 13212413105237 is 73250131421231.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11881160972836 + 1331252132401 = 3446906^2 + 1153799^2 .

It is a cyclic number.

It is not a de Polignac number, because 13212413105237 - 210 = 13212413104213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13212413105197 and 13212413105206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13212413105231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606206552618 + 6606206552619.

It is an arithmetic number, because the mean of its divisors is an integer number (6606206552619).

Almost surely, 213212413105237 is an apocalyptic number.

It is an amenable number.

13212413105237 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212413105237 is an equidigital number, since it uses as much as digits as its factorization.

13212413105237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 35.

Adding to 13212413105237 its reverse (73250131421231), we get a palindrome (86462544526468).

The spelling of 13212413105237 in words is "thirteen trillion, two hundred twelve billion, four hundred thirteen million, one hundred five thousand, two hundred thirty-seven".