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132124231401101 is a prime number
BaseRepresentation
bin11110000010101010010001…
…111000001111111010001101
3122022210221201212011012022122
4132002222101320033322031
5114304210411214313401
61145001011201022325
736554442423535352
oct3602522170177215
9568727655135278
10132124231401101
113910a632177435
121299a6899249a5
135895352855244
14248abbdd42629
151041cc3c6021b
hex782a91e0fe8d

132124231401101 has 2 divisors, whose sum is σ = 132124231401102. Its totient is φ = 132124231401100.

The previous prime is 132124231401077. The next prime is 132124231401119. The reversal of 132124231401101 is 101104132421231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130004440998601 + 2119790402500 = 11401949^2 + 1455950^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132124231401101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132124231401181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66062115700550 + 66062115700551.

It is an arithmetic number, because the mean of its divisors is an integer number (66062115700551).

Almost surely, 2132124231401101 is an apocalyptic number.

It is an amenable number.

132124231401101 is a deficient number, since it is larger than the sum of its proper divisors (1).

132124231401101 is an equidigital number, since it uses as much as digits as its factorization.

132124231401101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 132124231401101 its reverse (101104132421231), we get a palindrome (233228363822332).

The spelling of 132124231401101 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, two hundred thirty-one million, four hundred one thousand, one hundred one".