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13213032299981 is a prime number
BaseRepresentation
bin1100000001000110011000…
…0110001011110111001101
31201210011010221100122110222
43000101212012023313031
53212440242232044411
644033552214041125
72532416154311153
oct300214606136715
951704127318428
1013213032299981
1142346852a7848
1215949359491a5
1374aca2c780a7
1433972ac7d3d3
1517da7bcdd4db
hexc046618bdcd

13213032299981 has 2 divisors, whose sum is σ = 13213032299982. Its totient is φ = 13213032299980.

The previous prime is 13213032299893. The next prime is 13213032300007. The reversal of 13213032299981 is 18999223031231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9961970875081 + 3251061424900 = 3156259^2 + 1803070^2 .

It is a cyclic number.

It is not a de Polignac number, because 13213032299981 - 210 = 13213032298957 is a prime.

It is a super-2 number, since 2×132130322999812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13213032299081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606516149990 + 6606516149991.

It is an arithmetic number, because the mean of its divisors is an integer number (6606516149991).

Almost surely, 213213032299981 is an apocalyptic number.

It is an amenable number.

13213032299981 is a deficient number, since it is larger than the sum of its proper divisors (1).

13213032299981 is an equidigital number, since it uses as much as digits as its factorization.

13213032299981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1259712, while the sum is 53.

The spelling of 13213032299981 in words is "thirteen trillion, two hundred thirteen billion, thirty-two million, two hundred ninety-nine thousand, nine hundred eighty-one".