Base | Representation |
---|---|
bin | 1100000001000111000000… |
… | …1001110110001100101101 |
3 | 1201210011120200212010021022 |
4 | 3000101300021312030231 |
5 | 3212441113431010411 |
6 | 44034021042343525 |
7 | 2532423303436166 |
oct | 300216011661455 |
9 | 51704520763238 |
10 | 13213201031981 |
11 | 4234761573685 |
12 | 159498235aba5 |
13 | 74accbc05202 |
14 | 33974544276d |
15 | 17da8ba1cedb |
hex | c047027632d |
13213201031981 has 2 divisors, whose sum is σ = 13213201031982. Its totient is φ = 13213201031980.
The previous prime is 13213201031971. The next prime is 13213201031983. The reversal of 13213201031981 is 18913010231231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8981709302500 + 4231491729481 = 2996950^2 + 2057059^2 .
It is a cyclic number.
It is not a de Polignac number, because 13213201031981 - 222 = 13213196837677 is a prime.
It is a super-2 number, since 2×132132010319812 (a number of 27 digits) contains 22 as substring.
Together with 13213201031983, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13213201031983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606600515990 + 6606600515991.
It is an arithmetic number, because the mean of its divisors is an integer number (6606600515991).
Almost surely, 213213201031981 is an apocalyptic number.
It is an amenable number.
13213201031981 is a deficient number, since it is larger than the sum of its proper divisors (1).
13213201031981 is an equidigital number, since it uses as much as digits as its factorization.
13213201031981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 35.
The spelling of 13213201031981 in words is "thirteen trillion, two hundred thirteen billion, two hundred one million, thirty-one thousand, nine hundred eighty-one".
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