Base | Representation |
---|---|
bin | 11110000010110010011110… |
… | …011011111101010001001111 |
3 | 122022211210110012002010011021 |
4 | 132002302132123331101033 |
5 | 114304331422144214434 |
6 | 1145005024340535011 |
7 | 36555203465562451 |
oct | 3602623633752117 |
9 | 568753405063137 |
10 | 132133032023119 |
11 | 3911333896aa76 |
12 | 129a03250b1467 |
13 | 5896125c083aa |
14 | 248b3b6a982d1 |
15 | 104213b6a6cb4 |
hex | 782c9e6fd44f |
132133032023119 has 2 divisors, whose sum is σ = 132133032023120. Its totient is φ = 132133032023118.
The previous prime is 132133032023029. The next prime is 132133032023141. The reversal of 132133032023119 is 911320230331231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132133032023119 - 225 = 132132998468687 is a prime.
It is a super-2 number, since 2×1321330320231192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132133036023119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66066516011559 + 66066516011560.
It is an arithmetic number, because the mean of its divisors is an integer number (66066516011560).
Almost surely, 2132133032023119 is an apocalyptic number.
132133032023119 is a deficient number, since it is larger than the sum of its proper divisors (1).
132133032023119 is an equidigital number, since it uses as much as digits as its factorization.
132133032023119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 34.
The spelling of 132133032023119 in words is "one hundred thirty-two trillion, one hundred thirty-three billion, thirty-two million, twenty-three thousand, one hundred nineteen".
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