Base | Representation |
---|---|
bin | 11110000010110011011110… |
… | …110001011111111110100010 |
3 | 122022211220020102010202112001 |
4 | 132002303132301133332202 |
5 | 114304341130010142010 |
6 | 1145005323415554214 |
7 | 36555242313333262 |
oct | 3602633661377642 |
9 | 568756212122461 |
10 | 132134111412130 |
11 | 39113842187a03 |
12 | 129a058668b96a |
13 | 5896268720809 |
14 | 248b47a18d7a2 |
15 | 10421a131ac3a |
hex | 782cdec5ffa2 |
132134111412130 has 96 divisors (see below), whose sum is σ = 245828175989760. Its totient is φ = 51133482005760.
The previous prime is 132134111412101. The next prime is 132134111412131. The reversal of 132134111412130 is 31214111431231.
It is a super-2 number, since 2×1321341114121302 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (132134111412131) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 822780181 + ... + 822940759.
It is an arithmetic number, because the mean of its divisors is an integer number (2560710166560).
Almost surely, 2132134111412130 is an apocalyptic number.
132134111412130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132134111412130 is a deficient number, since it is larger than the sum of its proper divisors (113694064577630).
132134111412130 is a wasteful number, since it uses less digits than its factorization.
132134111412130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161096 (or 161053 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 28.
Adding to 132134111412130 its reverse (31214111431231), we get a palindrome (163348222843361).
The spelling of 132134111412130 in words is "one hundred thirty-two trillion, one hundred thirty-four billion, one hundred eleven million, four hundred twelve thousand, one hundred thirty".
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