Base | Representation |
---|---|
bin | 11000100111001111… |
… | …00111110000001000 |
3 | 1021002220120120022110 |
4 | 30103213213300020 |
5 | 204030244233212 |
6 | 10023115022320 |
7 | 645312421644 |
oct | 142347476010 |
9 | 37086516273 |
10 | 13214055432 |
11 | 5670a98476 |
12 | 268943a9a0 |
13 | 132783a716 |
14 | 8d4d69c24 |
15 | 525135a3c |
hex | 3139e7c08 |
13214055432 has 32 divisors (see below), whose sum is σ = 33362225280. Its totient is φ = 4361073600.
The previous prime is 13214055431. The next prime is 13214055467. The reversal of 13214055432 is 23455041231.
It is a super-2 number, since 2×132140554322 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13214055432.
It is not an unprimeable number, because it can be changed into a prime (13214055431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2723248 + ... + 2728095.
It is an arithmetic number, because the mean of its divisors is an integer number (1042569540).
Almost surely, 213214055432 is an apocalyptic number.
13214055432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13214055432 is an abundant number, since it is smaller than the sum of its proper divisors (20148169848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13214055432 is a wasteful number, since it uses less digits than its factorization.
13214055432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5451453 (or 5451449 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 13214055432 its reverse (23455041231), we get a palindrome (36669096663).
The spelling of 13214055432 in words is "thirteen billion, two hundred fourteen million, fifty-five thousand, four hundred thirty-two".
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