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132141120401093 is a prime number
BaseRepresentation
bin11110000010111010000000…
…100010101010111011000101
3122022212120022212210021211212
4132002322000202222323011
5114310000003310313333
61145012443114541205
736555611101631366
oct3602720042527305
9568776285707755
10132141120401093
1139116809611071
12129a1a01a37805
135896b1485306b
14248b942da9b6d
15104246180d448
hex782e808aaec5

132141120401093 has 2 divisors, whose sum is σ = 132141120401094. Its totient is φ = 132141120401092.

The previous prime is 132141120401083. The next prime is 132141120401117. The reversal of 132141120401093 is 390104021141231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127316762941729 + 4824357459364 = 11283473^2 + 2196442^2 .

It is an emirp because it is prime and its reverse (390104021141231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132141120401093 - 26 = 132141120401029 is a prime.

It is a super-2 number, since 2×1321411204010932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132141120401083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66070560200546 + 66070560200547.

It is an arithmetic number, because the mean of its divisors is an integer number (66070560200547).

Almost surely, 2132141120401093 is an apocalyptic number.

It is an amenable number.

132141120401093 is a deficient number, since it is larger than the sum of its proper divisors (1).

132141120401093 is an equidigital number, since it uses as much as digits as its factorization.

132141120401093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 132141120401093 in words is "one hundred thirty-two trillion, one hundred forty-one billion, one hundred twenty million, four hundred one thousand, ninety-three".