Search a number
-
+
132141200001253 is a prime number
BaseRepresentation
bin11110000010111010000101…
…010010010100100011100101
3122022212120112102120101201221
4132002322011102110203211
5114310000134200020003
61145012455041020341
736555613056341002
oct3602720522244345
9568776472511657
10132141200001253
113911684a539923
12129a1a246246b1
135896b281a3451
14248b94d7aa8a9
1510424687d37bd
hex782e854948e5

132141200001253 has 2 divisors, whose sum is σ = 132141200001254. Its totient is φ = 132141200001252.

The previous prime is 132141200001199. The next prime is 132141200001269. The reversal of 132141200001253 is 352100002141231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111627529244449 + 20513670756804 = 10565393^2 + 4529202^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132141200001253 is a prime.

It is a super-2 number, since 2×1321412000012532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132141200001053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66070600000626 + 66070600000627.

It is an arithmetic number, because the mean of its divisors is an integer number (66070600000627).

Almost surely, 2132141200001253 is an apocalyptic number.

It is an amenable number.

132141200001253 is a deficient number, since it is larger than the sum of its proper divisors (1).

132141200001253 is an equidigital number, since it uses as much as digits as its factorization.

132141200001253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 132141200001253 its reverse (352100002141231), we get a palindrome (484241202142484).

The spelling of 132141200001253 in words is "one hundred thirty-two trillion, one hundred forty-one billion, two hundred million, one thousand, two hundred fifty-three".