Base | Representation |
---|---|
bin | 11110000010111010001011… |
… | …111111010000001010010110 |
3 | 122022212120211021011000212012 |
4 | 132002322023333100022112 |
5 | 114310000401441134110 |
6 | 1145012514135024222 |
7 | 36555615623152412 |
oct | 3602721377201226 |
9 | 568776737130765 |
10 | 132141312443030 |
11 | 391168a7a59010 |
12 | 129a1a5620b072 |
13 | 5896b45582047 |
14 | 248b9606b9d42 |
15 | 10424735e4905 |
hex | 782e8bfd0296 |
132141312443030 has 16 divisors (see below), whose sum is σ = 259477486251984. Its totient is φ = 48051386342880.
The previous prime is 132141312443027. The next prime is 132141312443053. The reversal of 132141312443030 is 30344213141231.
It is a super-2 number, since 2×1321413124430302 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 600642329177 + ... + 600642329396.
It is an arithmetic number, because the mean of its divisors is an integer number (16217342890749).
Almost surely, 2132141312443030 is an apocalyptic number.
132141312443030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132141312443030 is a deficient number, since it is larger than the sum of its proper divisors (127336173808954).
132141312443030 is a wasteful number, since it uses less digits than its factorization.
132141312443030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1201284658591.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 132141312443030 its reverse (30344213141231), we get a palindrome (162485525584261).
The spelling of 132141312443030 in words is "one hundred thirty-two trillion, one hundred forty-one billion, three hundred twelve million, four hundred forty-three thousand, thirty".
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