13214243210471 has 2 divisors, whose sum is σ = 13214243210472. Its totient is φ = 13214243210470.

The previous prime is 13214243210353. The next prime is 13214243210473. The reversal of 13214243210471 is 17401234241231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13214243210471 - 2⁴² = 8816196699367 is a prime.

It is a super-3 number, since 3×13214243210471³ (a number of 40 digits) contains 333 as substring.

Together with 13214243210473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13214243210473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607121605235 + 6607121605236.

It is an arithmetic number, because the mean of its divisors is an integer number (6607121605236).

Almost surely, 2^{13214243210471} is an apocalyptic number.

13214243210471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13214243210471 is an equidigital number, since it uses as much as digits as its factorization.

13214243210471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 35.

The spelling of 13214243210471 in words is "thirteen trillion, two hundred fourteen billion, two hundred forty-three million, two hundred ten thousand, four hundred seventy-one".