Base | Representation |
---|---|
bin | 111101100010001101… |
… | …0010101100101111111 |
3 | 110122002100201210210211 |
4 | 1323010122111211333 |
5 | 4131112412214112 |
6 | 140412314013251 |
7 | 12355441440451 |
oct | 1730432254577 |
9 | 418070653724 |
10 | 132144257407 |
11 | 51050a96498 |
12 | 2173aa17227 |
13 | c5cc1b9cb6 |
14 | 65781962d1 |
15 | 368621e0a7 |
hex | 1ec469597f |
132144257407 has 2 divisors, whose sum is σ = 132144257408. Its totient is φ = 132144257406.
The previous prime is 132144257237. The next prime is 132144257467. The reversal of 132144257407 is 704752441231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132144257407 - 211 = 132144255359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132144257407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132144257467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66072128703 + 66072128704.
It is an arithmetic number, because the mean of its divisors is an integer number (66072128704).
Almost surely, 2132144257407 is an apocalyptic number.
132144257407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132144257407 is an equidigital number, since it uses as much as digits as its factorization.
132144257407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 188160, while the sum is 40.
Adding to 132144257407 its reverse (704752441231), we get a palindrome (836896698638).
The spelling of 132144257407 in words is "one hundred thirty-two billion, one hundred forty-four million, two hundred fifty-seven thousand, four hundred seven".
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