Base | Representation |
---|---|
bin | 11110000011000011010101… |
… | …001110100010001110000101 |
3 | 122022220112011112201112020221 |
4 | 132003003111032202032011 |
5 | 114310131004031324032 |
6 | 1145021220323224341 |
7 | 36556414136430325 |
oct | 3603032516421605 |
9 | 568815145645227 |
10 | 132151131120517 |
11 | 3911aa86387803 |
12 | 129a39365180b1 |
13 | 5897a4b824692 |
14 | 248c21271d285 |
15 | 104284a5d7597 |
hex | 7830d53a2385 |
132151131120517 has 2 divisors, whose sum is σ = 132151131120518. Its totient is φ = 132151131120516.
The previous prime is 132151131120457. The next prime is 132151131120523. The reversal of 132151131120517 is 715021131151231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72230434324801 + 59920696795716 = 8498849^2 + 7740846^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132151131120517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132151131120527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66075565560258 + 66075565560259.
It is an arithmetic number, because the mean of its divisors is an integer number (66075565560259).
Almost surely, 2132151131120517 is an apocalyptic number.
It is an amenable number.
132151131120517 is a deficient number, since it is larger than the sum of its proper divisors (1).
132151131120517 is an equidigital number, since it uses as much as digits as its factorization.
132151131120517 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 34.
Adding to 132151131120517 its reverse (715021131151231), we get a palindrome (847172262271748).
The spelling of 132151131120517 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred thirty-one million, one hundred twenty thousand, five hundred seventeen".
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