Base | Representation |
---|---|
bin | 11110000011000011011111… |
… | …111101110111010111001000 |
3 | 122022220112122002202121002121 |
4 | 132003003133331313113020 |
5 | 114310131341143100130 |
6 | 1145021250241141024 |
7 | 36556421455064134 |
oct | 3603033775672710 |
9 | 568815562677077 |
10 | 132151311300040 |
11 | 391200690622aa |
12 | 129a398692a774 |
13 | 5897a79c5c196 |
14 | 248c22c6223c4 |
15 | 104285b328d7a |
hex | 7830dff775c8 |
132151311300040 has 64 divisors (see below), whose sum is σ = 297840870696960. Its totient is φ = 52771567115520.
The previous prime is 132151311300007. The next prime is 132151311300059. The reversal of 132151311300040 is 40003113151231.
It is a junction number, because it is equal to n+sod(n) for n = 132151311299978 and 132151311300014.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 831777649 + ... + 831936511.
It is an arithmetic number, because the mean of its divisors is an integer number (4653763604640).
Almost surely, 2132151311300040 is an apocalyptic number.
132151311300040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132151311300040 is an abundant number, since it is smaller than the sum of its proper divisors (165689559396920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132151311300040 is a wasteful number, since it uses less digits than its factorization.
132151311300040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193742 (or 193738 counting only the distinct ones).
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 132151311300040 its reverse (40003113151231), we get a palindrome (172154424451271).
The spelling of 132151311300040 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, three hundred eleven million, three hundred thousand, forty".
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