Search a number
-
+
1321565543653 is a prime number
BaseRepresentation
bin10011001110110011011…
…100011101110011100101
311200100012011201120122011
4103032303130131303211
5133123031234344103
62451041400034221
7164323424526445
oct23166334356345
94610164646564
101321565543653
1146a522329343
12194165762971
1397813c32664
1447d6d756125
152459c335d6d
hex133b371dce5

1321565543653 has 2 divisors, whose sum is σ = 1321565543654. Its totient is φ = 1321565543652.

The previous prime is 1321565543651. The next prime is 1321565543677. The reversal of 1321565543653 is 3563455651231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1301064172164 + 20501371489 = 1140642^2 + 143183^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321565543653 - 21 = 1321565543651 is a prime.

Together with 1321565543651, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1321565543597 and 1321565543606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1321565543651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660782771826 + 660782771827.

It is an arithmetic number, because the mean of its divisors is an integer number (660782771827).

Almost surely, 21321565543653 is an apocalyptic number.

It is an amenable number.

1321565543653 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321565543653 is an equidigital number, since it uses as much as digits as its factorization.

1321565543653 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4860000, while the sum is 49.

The spelling of 1321565543653 in words is "one trillion, three hundred twenty-one billion, five hundred sixty-five million, five hundred forty-three thousand, six hundred fifty-three".