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132161547304733 is a prime number
BaseRepresentation
bin11110000011001101000010…
…000101000111111100011101
3122022221112001110121111210112
4132003031002011013330131
5114310313322102222413
61145030102054215405
736560233226511332
oct3603150205077435
9568845043544715
10132161547304733
1139124441011111
12129a5962954565
135898a1b7cbaab
14248c91dc5a989
151042c59ca42a8
hex783342147f1d

132161547304733 has 2 divisors, whose sum is σ = 132161547304734. Its totient is φ = 132161547304732.

The previous prime is 132161547304729. The next prime is 132161547304741. The reversal of 132161547304733 is 337403745161231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117711498357049 + 14450048947684 = 10849493^2 + 3801322^2 .

It is a cyclic number.

It is not a de Polignac number, because 132161547304733 - 22 = 132161547304729 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132161547304433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66080773652366 + 66080773652367.

It is an arithmetic number, because the mean of its divisors is an integer number (66080773652367).

Almost surely, 2132161547304733 is an apocalyptic number.

It is an amenable number.

132161547304733 is a deficient number, since it is larger than the sum of its proper divisors (1).

132161547304733 is an equidigital number, since it uses as much as digits as its factorization.

132161547304733 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3810240, while the sum is 50.

The spelling of 132161547304733 in words is "one hundred thirty-two trillion, one hundred sixty-one billion, five hundred forty-seven million, three hundred four thousand, seven hundred thirty-three".