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132161547304741 is a prime number
BaseRepresentation
bin11110000011001101000010…
…000101000111111100100101
3122022221112001110121111210211
4132003031002011013330211
5114310313322102222431
61145030102054215421
736560233226511343
oct3603150205077445
9568845043544724
10132161547304741
1139124441011119
12129a5962954571
135898a1b7cbab6
14248c91dc5a993
151042c59ca42b1
hex783342147f25

132161547304741 has 2 divisors, whose sum is σ = 132161547304742. Its totient is φ = 132161547304740.

The previous prime is 132161547304733. The next prime is 132161547304747. The reversal of 132161547304741 is 147403745161231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93998434887841 + 38163112416900 = 9695279^2 + 6177630^2 .

It is a cyclic number.

It is not a de Polignac number, because 132161547304741 - 23 = 132161547304733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132161547304747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66080773652370 + 66080773652371.

It is an arithmetic number, because the mean of its divisors is an integer number (66080773652371).

Almost surely, 2132161547304741 is an apocalyptic number.

It is an amenable number.

132161547304741 is a deficient number, since it is larger than the sum of its proper divisors (1).

132161547304741 is an equidigital number, since it uses as much as digits as its factorization.

132161547304741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1693440, while the sum is 49.

The spelling of 132161547304741 in words is "one hundred thirty-two trillion, one hundred sixty-one billion, five hundred forty-seven million, three hundred four thousand, seven hundred forty-one".