Base | Representation |
---|---|
bin | 11110000011001101100100… |
… | …010001110000000110110111 |
3 | 122022221120112110012022001101 |
4 | 132003031210101300012313 |
5 | 114310321010441242221 |
6 | 1145030235031310531 |
7 | 36560253364260655 |
oct | 3603154421600667 |
9 | 568846473168041 |
10 | 132162121040311 |
11 | 3912470596014a |
12 | 129a5aa2b1b447 |
13 | 5898ab062cabb |
14 | 248c976127dd5 |
15 | 1042c90334d91 |
hex | 7833644701b7 |
132162121040311 has 2 divisors, whose sum is σ = 132162121040312. Its totient is φ = 132162121040310.
The previous prime is 132162121040237. The next prime is 132162121040407. The reversal of 132162121040311 is 113040121261231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132162121040311 - 221 = 132162118943159 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132162121040311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132162121040611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66081060520155 + 66081060520156.
It is an arithmetic number, because the mean of its divisors is an integer number (66081060520156).
Almost surely, 2132162121040311 is an apocalyptic number.
132162121040311 is a deficient number, since it is larger than the sum of its proper divisors (1).
132162121040311 is an equidigital number, since it uses as much as digits as its factorization.
132162121040311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 28.
The spelling of 132162121040311 in words is "one hundred thirty-two trillion, one hundred sixty-two billion, one hundred twenty-one million, forty thousand, three hundred eleven".
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