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132162121040237 is a prime number
BaseRepresentation
bin11110000011001101100100…
…010001110000000101101101
3122022221120112110012021221122
4132003031210101300011231
5114310321010441241422
61145030235031310325
736560253364260521
oct3603154421600555
9568846473167848
10132162121040237
1139124705960092
12129a5aa2b1b3a5
135898ab062ca62
14248c976127d81
151042c90334d42
hex78336447016d

132162121040237 has 2 divisors, whose sum is σ = 132162121040238. Its totient is φ = 132162121040236.

The previous prime is 132162121040197. The next prime is 132162121040311. The reversal of 132162121040237 is 732040121261231.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132096266702596 + 65854337641 = 11493314^2 + 256621^2 .

It is a cyclic number.

It is not a de Polignac number, because 132162121040237 - 214 = 132162121023853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132162121040197 and 132162121040206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132162121040437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66081060520118 + 66081060520119.

It is an arithmetic number, because the mean of its divisors is an integer number (66081060520119).

Almost surely, 2132162121040237 is an apocalyptic number.

It is an amenable number.

132162121040237 is a deficient number, since it is larger than the sum of its proper divisors (1).

132162121040237 is an equidigital number, since it uses as much as digits as its factorization.

132162121040237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

The spelling of 132162121040237 in words is "one hundred thirty-two trillion, one hundred sixty-two billion, one hundred twenty-one million, forty thousand, two hundred thirty-seven".