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13216891223 is a prime number
BaseRepresentation
bin11000100111100100…
…11100000101010111
31021010002220122021202
430103302130011113
5204032011004343
610023255503115
7645345502364
oct142362340527
937102818252
1013216891223
115672654aa8
12268a387a9b
1313282c13c3
148d54a746b
155254e5db8
hex313c9c157

13216891223 has 2 divisors, whose sum is σ = 13216891224. Its totient is φ = 13216891222.

The previous prime is 13216891151. The next prime is 13216891229. The reversal of 13216891223 is 32219861231.

13216891223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13216891223 - 212 = 13216887127 is a prime.

It is a super-2 number, since 2×132168912232 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13216891229) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6608445611 + 6608445612.

It is an arithmetic number, because the mean of its divisors is an integer number (6608445612).

Almost surely, 213216891223 is an apocalyptic number.

13216891223 is a deficient number, since it is larger than the sum of its proper divisors (1).

13216891223 is an equidigital number, since it uses as much as digits as its factorization.

13216891223 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 38.

The spelling of 13216891223 in words is "thirteen billion, two hundred sixteen million, eight hundred ninety-one thousand, two hundred twenty-three".