Base | Representation |
---|---|
bin | 11110000011110001010000… |
… | …111111010110100001101111 |
3 | 122100002020110210221200222102 |
4 | 132003301100333112201233 |
5 | 114311433011222434003 |
6 | 1145100014352205315 |
7 | 36563111305341254 |
oct | 3603612077264157 |
9 | 570066423850872 |
10 | 132200452155503 |
11 | 39139995868346 |
12 | 129b13bbb3983b |
13 | 589c5aba0b554 |
14 | 2490770bcd42b |
15 | 1043c85562588 |
hex | 783c50fd686f |
132200452155503 has 2 divisors, whose sum is σ = 132200452155504. Its totient is φ = 132200452155502.
The previous prime is 132200452155491. The next prime is 132200452155511. The reversal of 132200452155503 is 305551254002231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132200452155503 - 222 = 132200447961199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132200452155703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100226077751 + 66100226077752.
It is an arithmetic number, because the mean of its divisors is an integer number (66100226077752).
Almost surely, 2132200452155503 is an apocalyptic number.
132200452155503 is a deficient number, since it is larger than the sum of its proper divisors (1).
132200452155503 is an equidigital number, since it uses as much as digits as its factorization.
132200452155503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180000, while the sum is 38.
The spelling of 132200452155503 in words is "one hundred thirty-two trillion, two hundred billion, four hundred fifty-two million, one hundred fifty-five thousand, five hundred three".
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