Base | Representation |
---|---|
bin | 11110000011110001111001… |
… | …101000111000100010001111 |
3 | 122100002022020100012122221212 |
4 | 132003301321220320202033 |
5 | 114311440410314200333 |
6 | 1145100210153245035 |
7 | 36563134226133104 |
oct | 3603617150704217 |
9 | 570068210178855 |
10 | 132201134131343 |
11 | 3913a205816942 |
12 | 129b157040377b |
13 | 589c68a0a9954 |
14 | 24907d75d4aab |
15 | 1043cc5374448 |
hex | 783c79a3888f |
132201134131343 has 2 divisors, whose sum is σ = 132201134131344. Its totient is φ = 132201134131342.
The previous prime is 132201134131333. The next prime is 132201134131361. The reversal of 132201134131343 is 343131431102231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132201134131343 - 26 = 132201134131279 is a prime.
It is a super-2 number, since 2×1322011341313432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132201134131333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100567065671 + 66100567065672.
It is an arithmetic number, because the mean of its divisors is an integer number (66100567065672).
Almost surely, 2132201134131343 is an apocalyptic number.
132201134131343 is a deficient number, since it is larger than the sum of its proper divisors (1).
132201134131343 is an equidigital number, since it uses as much as digits as its factorization.
132201134131343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 132201134131343 its reverse (343131431102231), we get a palindrome (475332565233574).
The spelling of 132201134131343 in words is "one hundred thirty-two trillion, two hundred one billion, one hundred thirty-four million, one hundred thirty-one thousand, three hundred forty-three".
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