Base | Representation |
---|---|
bin | 1100000001100001100000… |
… | …0001010000110100011111 |
3 | 1201210211221022000001022121 |
4 | 3000120120001100310133 |
5 | 3213100144423240221 |
6 | 44041154434123411 |
7 | 2533064443420144 |
oct | 300303001206437 |
9 | 51724838001277 |
10 | 13220312321311 |
11 | 423778071a5a7 |
12 | 1596227a20567 |
13 | 74b8932a5314 |
14 | 339c1ba8c3cb |
15 | 17dd55ebba41 |
hex | c0618050d1f |
13220312321311 has 2 divisors, whose sum is σ = 13220312321312. Its totient is φ = 13220312321310.
The previous prime is 13220312321261. The next prime is 13220312321347. The reversal of 13220312321311 is 11312321302231.
It is a strong prime.
It is an emirp because it is prime and its reverse (11312321302231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13220312321311 - 213 = 13220312313119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13220312321911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610156160655 + 6610156160656.
It is an arithmetic number, because the mean of its divisors is an integer number (6610156160656).
Almost surely, 213220312321311 is an apocalyptic number.
13220312321311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13220312321311 is an equidigital number, since it uses as much as digits as its factorization.
13220312321311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13220312321311 its reverse (11312321302231), we get a palindrome (24532633623542).
The spelling of 13220312321311 in words is "thirteen trillion, two hundred twenty billion, three hundred twelve million, three hundred twenty-one thousand, three hundred eleven".
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