Base | Representation |
---|---|
bin | 11110000011111011000110… |
… | …011110010010001110011011 |
3 | 122100010020201211021221211221 |
4 | 132003323012132102032123 |
5 | 114312121123330230321 |
6 | 1145104522334432511 |
7 | 36563634104225605 |
oct | 3603730636221633 |
9 | 570106654257757 |
10 | 132211013133211 |
11 | 391434151a81a1 |
12 | 129b3468962737 |
13 | 58a05a29b0a9c |
14 | 249109365c175 |
15 | 10441a27d0e41 |
hex | 783ec679239b |
132211013133211 has 2 divisors, whose sum is σ = 132211013133212. Its totient is φ = 132211013133210.
The previous prime is 132211013133209. The next prime is 132211013133281. The reversal of 132211013133211 is 112331310112231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132211013133211 - 21 = 132211013133209 is a prime.
Together with 132211013133209, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132211013133281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66105506566605 + 66105506566606.
It is an arithmetic number, because the mean of its divisors is an integer number (66105506566606).
Almost surely, 2132211013133211 is an apocalyptic number.
132211013133211 is a deficient number, since it is larger than the sum of its proper divisors (1).
132211013133211 is an equidigital number, since it uses as much as digits as its factorization.
132211013133211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 132211013133211 its reverse (112331310112231), we get a palindrome (244542323245442).
The spelling of 132211013133211 in words is "one hundred thirty-two trillion, two hundred eleven billion, thirteen million, one hundred thirty-three thousand, two hundred eleven".
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