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132212214204043 is a prime number
BaseRepresentation
bin11110000011111100001110…
…000100000000011010001011
3122100010100211112022200021211
4132003330032010000122023
5114312131103314012133
61145105241441513551
736564005630164051
oct3603741604003213
9570110745280254
10132212214204043
1139143981175516
12129b37430428b7
1358a073478b79c
142491168d8a1d1
151044222e7dbcd
hex783f0e10068b

132212214204043 has 2 divisors, whose sum is σ = 132212214204044. Its totient is φ = 132212214204042.

The previous prime is 132212214204041. The next prime is 132212214204121. The reversal of 132212214204043 is 340402412212231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132212214204043 - 21 = 132212214204041 is a prime.

Together with 132212214204041, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 132212214203996 and 132212214204014.

It is not a weakly prime, because it can be changed into another prime (132212214204041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106107102021 + 66106107102022.

It is an arithmetic number, because the mean of its divisors is an integer number (66106107102022).

Almost surely, 2132212214204043 is an apocalyptic number.

132212214204043 is a deficient number, since it is larger than the sum of its proper divisors (1).

132212214204043 is an equidigital number, since it uses as much as digits as its factorization.

132212214204043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 132212214204043 its reverse (340402412212231), we get a palindrome (472614626416274).

The spelling of 132212214204043 in words is "one hundred thirty-two trillion, two hundred twelve billion, two hundred fourteen million, two hundred four thousand, forty-three".