132212214204041 has 2 divisors, whose sum is σ = 132212214204042. Its totient is φ = 132212214204040.

The previous prime is 132212214203959. The next prime is 132212214204043. The reversal of 132212214204041 is 140402412212231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115704529612816 + 16507684591225 = 10756604^2 + 4062965^2 .

It is a cyclic number.

It is not a de Polignac number, because 132212214204041 - 2²⁶ = 132212147095177 is a prime.

Together with 132212214204043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132212214203995 and 132212214204013.

It is not a weakly prime, because it can be changed into another prime (132212214204043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66106107102020 + 66106107102021.

It is an arithmetic number, because the mean of its divisors is an integer number (66106107102021).

Almost surely, 2^{132212214204041} is an apocalyptic number.

It is an amenable number.

132212214204041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132212214204041 is an equidigital number, since it uses as much as digits as its factorization.

132212214204041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 132212214204041 its reverse (140402412212231), we get a palindrome (272614626416272).

The spelling of 132212214204041 in words is "one hundred thirty-two trillion, two hundred twelve billion, two hundred fourteen million, two hundred four thousand, forty-one".