Base | Representation |
---|---|
bin | 1100000001100101001110… |
… | …1100001111110000100111 |
3 | 1201210221112001210101201011 |
4 | 3000121103230033300213 |
5 | 3213104222220214103 |
6 | 44041442035443051 |
7 | 2533131321010624 |
oct | 300312354176047 |
9 | 51727461711634 |
10 | 13221313444903 |
11 | 4238144840573 |
12 | 1596467156487 |
13 | 74b9c2816a45 |
14 | 339cb4a0d34b |
15 | 17ddb3d20d6d |
hex | c0653b0fc27 |
13221313444903 has 2 divisors, whose sum is σ = 13221313444904. Its totient is φ = 13221313444902.
The previous prime is 13221313444877. The next prime is 13221313444919. The reversal of 13221313444903 is 30944431312231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13221313444903 - 213 = 13221313436711 is a prime.
It is a super-3 number, since 3×132213134449033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13221313444943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610656722451 + 6610656722452.
It is an arithmetic number, because the mean of its divisors is an integer number (6610656722452).
Almost surely, 213221313444903 is an apocalyptic number.
13221313444903 is a deficient number, since it is larger than the sum of its proper divisors (1).
13221313444903 is an equidigital number, since it uses as much as digits as its factorization.
13221313444903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 40.
The spelling of 13221313444903 in words is "thirteen trillion, two hundred twenty-one billion, three hundred thirteen million, four hundred forty-four thousand, nine hundred three".
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