Base | Representation |
---|---|
bin | 11110000011111110110100… |
… | …010111011101101100001011 |
3 | 122100010122000222102101101002 |
4 | 132003332310113131230023 |
5 | 114312202312101310241 |
6 | 1145110422351445215 |
7 | 36564135026615312 |
oct | 3603766427355413 |
9 | 570118028371332 |
10 | 132215004322571 |
11 | 391450831138a5 |
12 | 129b41a152680b |
13 | 58a0a8a8390b1 |
14 | 249135175b279 |
15 | 1044337db589b |
hex | 783fb45ddb0b |
132215004322571 has 2 divisors, whose sum is σ = 132215004322572. Its totient is φ = 132215004322570.
The previous prime is 132215004322543. The next prime is 132215004322573. The reversal of 132215004322571 is 175223400512231.
It is a strong prime.
It is an emirp because it is prime and its reverse (175223400512231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132215004322571 - 230 = 132213930580747 is a prime.
Together with 132215004322573, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132215004322573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107502161285 + 66107502161286.
It is an arithmetic number, because the mean of its divisors is an integer number (66107502161286).
Almost surely, 2132215004322571 is an apocalyptic number.
132215004322571 is a deficient number, since it is larger than the sum of its proper divisors (1).
132215004322571 is an equidigital number, since it uses as much as digits as its factorization.
132215004322571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 38.
The spelling of 132215004322571 in words is "one hundred thirty-two trillion, two hundred fifteen billion, four million, three hundred twenty-two thousand, five hundred seventy-one".
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