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132220122453373 is a prime number
BaseRepresentation
bin11110000100000011100101…
…011011100101010101111101
3122100011010020200002100221011
4132010003211123211111331
5114312243302322001443
61145113030303035221
736564405615200413
oct3604034533452575
9570133220070834
10132220122453373
113914726a176269
12129b518b59bb11
1358a13c4cb8b66
1424916b93ad2b3
1510445373a3b9d
hex7840e56e557d

132220122453373 has 2 divisors, whose sum is σ = 132220122453374. Its totient is φ = 132220122453372.

The previous prime is 132220122453323. The next prime is 132220122453407. The reversal of 132220122453373 is 373354221022231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122485859732889 + 9734262720484 = 11067333^2 + 3119978^2 .

It is a cyclic number.

It is not a de Polignac number, because 132220122453373 - 213 = 132220122445181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132220122453323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110061226686 + 66110061226687.

It is an arithmetic number, because the mean of its divisors is an integer number (66110061226687).

Almost surely, 2132220122453373 is an apocalyptic number.

It is an amenable number.

132220122453373 is a deficient number, since it is larger than the sum of its proper divisors (1).

132220122453373 is an equidigital number, since it uses as much as digits as its factorization.

132220122453373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 40.

The spelling of 132220122453373 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred twenty-two million, four hundred fifty-three thousand, three hundred seventy-three".