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132220122453407 is a prime number
BaseRepresentation
bin11110000100000011100101…
…011011100101010110011111
3122100011010020200002100222102
4132010003211123211112133
5114312243302322002112
61145113030303035315
736564405615200462
oct3604034533452637
9570133220070872
10132220122453407
113914726a17629a
12129b518b59bb3b
1358a13c4cb8b91
1424916b93ad2d9
1510445373a3bc2
hex7840e56e559f

132220122453407 has 2 divisors, whose sum is σ = 132220122453408. Its totient is φ = 132220122453406.

The previous prime is 132220122453373. The next prime is 132220122453421. The reversal of 132220122453407 is 704354221022231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132220122453407 - 28 = 132220122453151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132220122453427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110061226703 + 66110061226704.

It is an arithmetic number, because the mean of its divisors is an integer number (66110061226704).

Almost surely, 2132220122453407 is an apocalyptic number.

132220122453407 is a deficient number, since it is larger than the sum of its proper divisors (1).

132220122453407 is an equidigital number, since it uses as much as digits as its factorization.

132220122453407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 38.

Adding to 132220122453407 its reverse (704354221022231), we get a palindrome (836574343475638).

The spelling of 132220122453407 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred twenty-two million, four hundred fifty-three thousand, four hundred seven".