Base | Representation |
---|---|
bin | 11110000100000011100101… |
… | …011011100101010110011111 |
3 | 122100011010020200002100222102 |
4 | 132010003211123211112133 |
5 | 114312243302322002112 |
6 | 1145113030303035315 |
7 | 36564405615200462 |
oct | 3604034533452637 |
9 | 570133220070872 |
10 | 132220122453407 |
11 | 3914726a17629a |
12 | 129b518b59bb3b |
13 | 58a13c4cb8b91 |
14 | 24916b93ad2d9 |
15 | 10445373a3bc2 |
hex | 7840e56e559f |
132220122453407 has 2 divisors, whose sum is σ = 132220122453408. Its totient is φ = 132220122453406.
The previous prime is 132220122453373. The next prime is 132220122453421. The reversal of 132220122453407 is 704354221022231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132220122453407 - 28 = 132220122453151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132220122453427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110061226703 + 66110061226704.
It is an arithmetic number, because the mean of its divisors is an integer number (66110061226704).
Almost surely, 2132220122453407 is an apocalyptic number.
132220122453407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220122453407 is an equidigital number, since it uses as much as digits as its factorization.
132220122453407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 38.
Adding to 132220122453407 its reverse (704354221022231), we get a palindrome (836574343475638).
The spelling of 132220122453407 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred twenty-two million, four hundred fifty-three thousand, four hundred seven".
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