Base | Representation |
---|---|
bin | 11110000100000011111100… |
… | …000001100110111011111100 |
3 | 122100011011020002100221202110 |
4 | 132010003330001212323330 |
5 | 114312300041342120444 |
6 | 1145113132043454020 |
7 | 36564421200205323 |
oct | 3604037401467374 |
9 | 570134202327673 |
10 | 132220501520124 |
11 | 39147444143776 |
12 | 129b5276527310 |
13 | 58a14556ab304 |
14 | 24917138850ba |
15 | 104455a7cecb9 |
hex | 7840fc066efc |
132220501520124 has 24 divisors (see below), whose sum is σ = 308706246602320. Its totient is φ = 44046108641664.
The previous prime is 132220501520113. The next prime is 132220501520167. The reversal of 132220501520124 is 421025105022231.
It is a super-2 number, since 2×1322205015201242 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132220501520091 and 132220501520100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3423963019 + ... + 3424001634.
Almost surely, 2132220501520124 is an apocalyptic number.
It is an amenable number.
132220501520124 is an abundant number, since it is smaller than the sum of its proper divisors (176485745082196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132220501520124 is a wasteful number, since it uses less digits than its factorization.
132220501520124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6847966269 (or 6847966267 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 132220501520124 its reverse (421025105022231), we get a palindrome (553245606542355).
The spelling of 132220501520124 in words is "one hundred thirty-two trillion, two hundred twenty billion, five hundred one million, five hundred twenty thousand, one hundred twenty-four".
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