Base | Representation |
---|---|
bin | 11110000100000100011001… |
… | …110011101111101001111100 |
3 | 122100011012111220121102211201 |
4 | 132010010121303233221330 |
5 | 114312302102301433200 |
6 | 1145113253413425244 |
7 | 36564436445346553 |
oct | 3604043163575174 |
9 | 570135456542751 |
10 | 132221001202300 |
11 | 3914768020334a |
12 | 129b539593b224 |
13 | 58a150508183a |
14 | 249175dd96d9a |
15 | 10445895d3c6a |
hex | 784119cefa7c |
132221001202300 has 36 divisors (see below), whose sum is σ = 288035991235440. Its totient is φ = 52682609029120.
The previous prime is 132221001202211. The next prime is 132221001202319. The reversal of 132221001202300 is 3202100122231.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2572367320 + ... + 2572418719.
It is an arithmetic number, because the mean of its divisors is an integer number (8000999756540).
Almost surely, 2132221001202300 is an apocalyptic number.
132221001202300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132221001202300 is an abundant number, since it is smaller than the sum of its proper divisors (155814990033140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132221001202300 is a wasteful number, since it uses less digits than its factorization.
132221001202300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5144786310 (or 5144786303 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 132221001202300 its reverse (3202100122231), we get a palindrome (135423101324531).
The spelling of 132221001202300 in words is "one hundred thirty-two trillion, two hundred twenty-one billion, one million, two hundred two thousand, three hundred".
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