Base | Representation |
---|---|
bin | 11000101000001100… |
… | …11011010110111010 |
3 | 1021010110202212002101 |
4 | 30110012123112322 |
5 | 204034331144010 |
6 | 10024004054014 |
7 | 645441155155 |
oct | 142406332672 |
9 | 37113685071 |
10 | 13222131130 |
11 | 56756038aa |
12 | 269009430a |
13 | 1329407440 |
14 | 8d606cc9c |
15 | 525bcd73a |
hex | 31419b5ba |
13222131130 has 64 divisors (see below), whose sum is σ = 25993094400. Its totient is φ = 4813433856.
The previous prime is 13222131121. The next prime is 13222131137. The reversal of 13222131130 is 3113122231.
13222131130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13222131098 and 13222131107.
It is not an unprimeable number, because it can be changed into a prime (13222131137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2921049 + ... + 2925571.
It is an arithmetic number, because the mean of its divisors is an integer number (406142100).
Almost surely, 213222131130 is an apocalyptic number.
13222131130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13222131130 is a deficient number, since it is larger than the sum of its proper divisors (12770963270).
13222131130 is a wasteful number, since it uses less digits than its factorization.
13222131130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4855.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13222131130 its reverse (3113122231), we get a palindrome (16335253361).
The spelling of 13222131130 in words is "thirteen billion, two hundred twenty-two million, one hundred thirty-one thousand, one hundred thirty".
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