Base | Representation |
---|---|
bin | 11000101000001111… |
… | …00100110100010011 |
3 | 1021010111100010211102 |
4 | 30110013210310103 |
5 | 204034420311034 |
6 | 10024014335015 |
7 | 645443550326 |
oct | 142407446423 |
9 | 37114303742 |
10 | 13222432019 |
11 | 5675799975 |
12 | 26901ba46b |
13 | 13294b1394 |
14 | 8d610a7bd |
15 | 525c3c97e |
hex | 3141e4d13 |
13222432019 has 2 divisors, whose sum is σ = 13222432020. Its totient is φ = 13222432018.
The previous prime is 13222432007. The next prime is 13222432021. The reversal of 13222432019 is 91023422231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13222432019 - 28 = 13222431763 is a prime.
It is a super-2 number, since 2×132224320192 (a number of 21 digits) contains 22 as substring.
Together with 13222432021, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13222431982 and 13222432000.
It is not a weakly prime, because it can be changed into another prime (13222432099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611216009 + 6611216010.
It is an arithmetic number, because the mean of its divisors is an integer number (6611216010).
Almost surely, 213222432019 is an apocalyptic number.
13222432019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222432019 is an equidigital number, since it uses as much as digits as its factorization.
13222432019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 13222432019 in words is "thirteen billion, two hundred twenty-two million, four hundred thirty-two thousand, nineteen".
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