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132225445641461 is a prime number
BaseRepresentation
bin11110000100001000100010…
…101101111011110011110101
3122100011121222122121100012112
4132010020202231323303311
5114312340203041011321
61145115310421300405
736564654543432254
oct3604104255736365
9570147878540175
10132225445641461
1139149550a55267
12129b6216264705
1358a1a62aa3ab3
142491a6235c79b
151044749899a5b
hex784222b7bcf5

132225445641461 has 2 divisors, whose sum is σ = 132225445641462. Its totient is φ = 132225445641460.

The previous prime is 132225445641409. The next prime is 132225445641463. The reversal of 132225445641461 is 164146544522231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97974976929361 + 34250468712100 = 9898231^2 + 5852390^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132225445641461 is a prime.

Together with 132225445641463, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132225445641463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66112722820730 + 66112722820731.

It is an arithmetic number, because the mean of its divisors is an integer number (66112722820731).

Almost surely, 2132225445641461 is an apocalyptic number.

It is an amenable number.

132225445641461 is a deficient number, since it is larger than the sum of its proper divisors (1).

132225445641461 is an equidigital number, since it uses as much as digits as its factorization.

132225445641461 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5529600, while the sum is 50.

The spelling of 132225445641461 in words is "one hundred thirty-two trillion, two hundred twenty-five billion, four hundred forty-five million, six hundred forty-one thousand, four hundred sixty-one".