Base | Representation |
---|---|
bin | 11110000100011001010001… |
… | …000100011001011111000100 |
3 | 122100020100100010211100200112 |
4 | 132010121101010121133010 |
5 | 114313133442201320200 |
6 | 1145131440345132152 |
7 | 36566161544645330 |
oct | 3604312104313704 |
9 | 570210303740615 |
10 | 132243403151300 |
11 | 39156126556191 |
12 | 129b97a818a058 |
13 | 58a366527826c |
14 | 24928872887c0 |
15 | 1044e4b15d535 |
hex | 7846511197c4 |
132243403151300 has 72 divisors (see below), whose sum is σ = 328202508653376. Its totient is φ = 45307572024960.
The previous prime is 132243403151287. The next prime is 132243403151323. The reversal of 132243403151300 is 3151304342231.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 67836842 + ... + 69759041.
Almost surely, 2132243403151300 is an apocalyptic number.
132243403151300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132243403151300 is an abundant number, since it is smaller than the sum of its proper divisors (195959105502076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132243403151300 is a wasteful number, since it uses less digits than its factorization.
132243403151300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137597277 (or 137597270 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 132243403151300 its reverse (3151304342231), we get a palindrome (135394707493531).
The spelling of 132243403151300 in words is "one hundred thirty-two trillion, two hundred forty-three billion, four hundred three million, one hundred fifty-one thousand, three hundred".
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