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13225000001 is a prime number
BaseRepresentation
bin11000101000100010…
…10111110001000001
31021010200011121102212
430110101113301001
5204041100000001
610024145351505
7645504434213
oct142421276101
937120147385
1013225000001
115677193274
122691038595
131329ba01b5
148d65b85b3
155260987bb
hex314457c41

13225000001 has 2 divisors, whose sum is σ = 13225000002. Its totient is φ = 13225000000.

The previous prime is 13224999979. The next prime is 13225000003. The reversal of 13225000001 is 10000052231.

It is a happy number.

It is a Cunningham number, because it is equal to 1150002+1.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13225000000 + 1 = 115000^2 + 1^2 .

It is a cyclic number.

It is not a de Polignac number, because 13225000001 - 210 = 13224998977 is a prime.

Together with 13225000003, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13225000001.

It is not a weakly prime, because it can be changed into another prime (13225000003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612500000 + 6612500001.

It is an arithmetic number, because the mean of its divisors is an integer number (6612500001).

Almost surely, 213225000001 is an apocalyptic number.

It is an amenable number.

13225000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13225000001 is an equidigital number, since it uses as much as digits as its factorization.

13225000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 13225000001 its reverse (10000052231), we get a palindrome (23225052232).

The spelling of 13225000001 in words is "thirteen billion, two hundred twenty-five million, one", and thus it is an aban number.