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13230014421311 is a prime number
BaseRepresentation
bin1100000010000101101001…
…0011110101100100111111
31201211202222110012210110122
43000201122103311210333
53213230032142440221
644045441255525155
72533560043050032
oct300413223654477
951752873183418
1013230014421311
1142408aa264966
1215980950897bb
1374c77b34b7ac
1433a49c427019
1517e222b32eab
hexc085a4f593f

13230014421311 has 2 divisors, whose sum is σ = 13230014421312. Its totient is φ = 13230014421310.

The previous prime is 13230014421233. The next prime is 13230014421313. The reversal of 13230014421311 is 11312441003231.

13230014421311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13230014421311 - 214 = 13230014404927 is a prime.

It is a Sophie Germain prime.

Together with 13230014421313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13230014421313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615007210655 + 6615007210656.

It is an arithmetic number, because the mean of its divisors is an integer number (6615007210656).

Almost surely, 213230014421311 is an apocalyptic number.

13230014421311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13230014421311 is an equidigital number, since it uses as much as digits as its factorization.

13230014421311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 13230014421311 its reverse (11312441003231), we get a palindrome (24542455424542).

The spelling of 13230014421311 in words is "thirteen trillion, two hundred thirty billion, fourteen million, four hundred twenty-one thousand, three hundred eleven".